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x2-15x-10^3=0
We add all the numbers together, and all the variables
x^2-15x-1000=0
a = 1; b = -15; c = -1000;
Δ = b2-4ac
Δ = -152-4·1·(-1000)
Δ = 4225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4225}=65$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-65}{2*1}=\frac{-50}{2} =-25 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+65}{2*1}=\frac{80}{2} =40 $
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